Optimal. Leaf size=172 \[ \frac{52 \text{EllipticF}\left (\frac{1}{2} \left (c+d x-\frac{\pi }{2}\right ),2\right )}{21 a^2 d e^3 \sqrt{\sin (c+d x)} \sqrt{e \csc (c+d x)}}-\frac{4}{a^2 d e^3 \sqrt{e \csc (c+d x)}}+\frac{2 \cos ^3(c+d x)}{7 a^2 d e^3 \sqrt{e \csc (c+d x)}}+\frac{26 \cos (c+d x)}{21 a^2 d e^3 \sqrt{e \csc (c+d x)}}+\frac{4 \sin ^2(c+d x)}{5 a^2 d e^3 \sqrt{e \csc (c+d x)}} \]
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Rubi [A] time = 0.463165, antiderivative size = 172, normalized size of antiderivative = 1., number of steps used = 13, number of rules used = 8, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.32, Rules used = {3878, 3872, 2875, 2873, 2569, 2641, 2564, 14} \[ -\frac{4}{a^2 d e^3 \sqrt{e \csc (c+d x)}}+\frac{2 \cos ^3(c+d x)}{7 a^2 d e^3 \sqrt{e \csc (c+d x)}}+\frac{26 \cos (c+d x)}{21 a^2 d e^3 \sqrt{e \csc (c+d x)}}+\frac{4 \sin ^2(c+d x)}{5 a^2 d e^3 \sqrt{e \csc (c+d x)}}+\frac{52 F\left (\left .\frac{1}{2} \left (c+d x-\frac{\pi }{2}\right )\right |2\right )}{21 a^2 d e^3 \sqrt{\sin (c+d x)} \sqrt{e \csc (c+d x)}} \]
Antiderivative was successfully verified.
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Rule 3878
Rule 3872
Rule 2875
Rule 2873
Rule 2569
Rule 2641
Rule 2564
Rule 14
Rubi steps
\begin{align*} \int \frac{1}{(e \csc (c+d x))^{7/2} (a+a \sec (c+d x))^2} \, dx &=\frac{\int \frac{\sin ^{\frac{7}{2}}(c+d x)}{(a+a \sec (c+d x))^2} \, dx}{e^3 \sqrt{e \csc (c+d x)} \sqrt{\sin (c+d x)}}\\ &=\frac{\int \frac{\cos ^2(c+d x) \sin ^{\frac{7}{2}}(c+d x)}{(-a-a \cos (c+d x))^2} \, dx}{e^3 \sqrt{e \csc (c+d x)} \sqrt{\sin (c+d x)}}\\ &=\frac{\int \frac{\cos ^2(c+d x) (-a+a \cos (c+d x))^2}{\sqrt{\sin (c+d x)}} \, dx}{a^4 e^3 \sqrt{e \csc (c+d x)} \sqrt{\sin (c+d x)}}\\ &=\frac{\int \left (\frac{a^2 \cos ^2(c+d x)}{\sqrt{\sin (c+d x)}}-\frac{2 a^2 \cos ^3(c+d x)}{\sqrt{\sin (c+d x)}}+\frac{a^2 \cos ^4(c+d x)}{\sqrt{\sin (c+d x)}}\right ) \, dx}{a^4 e^3 \sqrt{e \csc (c+d x)} \sqrt{\sin (c+d x)}}\\ &=\frac{\int \frac{\cos ^2(c+d x)}{\sqrt{\sin (c+d x)}} \, dx}{a^2 e^3 \sqrt{e \csc (c+d x)} \sqrt{\sin (c+d x)}}+\frac{\int \frac{\cos ^4(c+d x)}{\sqrt{\sin (c+d x)}} \, dx}{a^2 e^3 \sqrt{e \csc (c+d x)} \sqrt{\sin (c+d x)}}-\frac{2 \int \frac{\cos ^3(c+d x)}{\sqrt{\sin (c+d x)}} \, dx}{a^2 e^3 \sqrt{e \csc (c+d x)} \sqrt{\sin (c+d x)}}\\ &=\frac{2 \cos (c+d x)}{3 a^2 d e^3 \sqrt{e \csc (c+d x)}}+\frac{2 \cos ^3(c+d x)}{7 a^2 d e^3 \sqrt{e \csc (c+d x)}}+\frac{2 \int \frac{1}{\sqrt{\sin (c+d x)}} \, dx}{3 a^2 e^3 \sqrt{e \csc (c+d x)} \sqrt{\sin (c+d x)}}+\frac{6 \int \frac{\cos ^2(c+d x)}{\sqrt{\sin (c+d x)}} \, dx}{7 a^2 e^3 \sqrt{e \csc (c+d x)} \sqrt{\sin (c+d x)}}-\frac{2 \operatorname{Subst}\left (\int \frac{1-x^2}{\sqrt{x}} \, dx,x,\sin (c+d x)\right )}{a^2 d e^3 \sqrt{e \csc (c+d x)} \sqrt{\sin (c+d x)}}\\ &=\frac{26 \cos (c+d x)}{21 a^2 d e^3 \sqrt{e \csc (c+d x)}}+\frac{2 \cos ^3(c+d x)}{7 a^2 d e^3 \sqrt{e \csc (c+d x)}}+\frac{4 F\left (\left .\frac{1}{2} \left (c-\frac{\pi }{2}+d x\right )\right |2\right )}{3 a^2 d e^3 \sqrt{e \csc (c+d x)} \sqrt{\sin (c+d x)}}+\frac{4 \int \frac{1}{\sqrt{\sin (c+d x)}} \, dx}{7 a^2 e^3 \sqrt{e \csc (c+d x)} \sqrt{\sin (c+d x)}}-\frac{2 \operatorname{Subst}\left (\int \left (\frac{1}{\sqrt{x}}-x^{3/2}\right ) \, dx,x,\sin (c+d x)\right )}{a^2 d e^3 \sqrt{e \csc (c+d x)} \sqrt{\sin (c+d x)}}\\ &=-\frac{4}{a^2 d e^3 \sqrt{e \csc (c+d x)}}+\frac{26 \cos (c+d x)}{21 a^2 d e^3 \sqrt{e \csc (c+d x)}}+\frac{2 \cos ^3(c+d x)}{7 a^2 d e^3 \sqrt{e \csc (c+d x)}}+\frac{52 F\left (\left .\frac{1}{2} \left (c-\frac{\pi }{2}+d x\right )\right |2\right )}{21 a^2 d e^3 \sqrt{e \csc (c+d x)} \sqrt{\sin (c+d x)}}+\frac{4 \sin ^2(c+d x)}{5 a^2 d e^3 \sqrt{e \csc (c+d x)}}\\ \end{align*}
Mathematica [A] time = 2.27638, size = 94, normalized size = 0.55 \[ \frac{\sqrt{\sin (c+d x)} \sqrt{e \csc (c+d x)} \left (\sqrt{\sin (c+d x)} (305 \cos (c+d x)-84 \cos (2 (c+d x))+15 \cos (3 (c+d x))-756)-520 \text{EllipticF}\left (\frac{1}{4} (-2 c-2 d x+\pi ),2\right )\right )}{210 a^2 d e^4} \]
Antiderivative was successfully verified.
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Maple [C] time = 0.208, size = 221, normalized size = 1.3 \begin{align*} -{\frac{\sqrt{2}}{105\,d{a}^{2} \left ( -1+\cos \left ( dx+c \right ) \right ) \left ( \sin \left ( dx+c \right ) \right ) ^{3}} \left ( 130\,i\sin \left ( dx+c \right ) \sqrt{{\frac{-i \left ( -1+\cos \left ( dx+c \right ) \right ) }{\sin \left ( dx+c \right ) }}}\sqrt{{\frac{i\cos \left ( dx+c \right ) +\sin \left ( dx+c \right ) -i}{\sin \left ( dx+c \right ) }}}\sqrt{{\frac{-i\cos \left ( dx+c \right ) +\sin \left ( dx+c \right ) +i}{\sin \left ( dx+c \right ) }}}{\it EllipticF} \left ( \sqrt{{\frac{i\cos \left ( dx+c \right ) +\sin \left ( dx+c \right ) -i}{\sin \left ( dx+c \right ) }}},{\frac{\sqrt{2}}{2}} \right ) -15\,\sqrt{2} \left ( \cos \left ( dx+c \right ) \right ) ^{4}+57\, \left ( \cos \left ( dx+c \right ) \right ) ^{3}\sqrt{2}-107\, \left ( \cos \left ( dx+c \right ) \right ) ^{2}\sqrt{2}+233\,\cos \left ( dx+c \right ) \sqrt{2}-168\,\sqrt{2} \right ) \left ({\frac{e}{\sin \left ( dx+c \right ) }} \right ) ^{-{\frac{7}{2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sqrt{e \csc \left (d x + c\right )}}{a^{2} e^{4} \csc \left (d x + c\right )^{4} \sec \left (d x + c\right )^{2} + 2 \, a^{2} e^{4} \csc \left (d x + c\right )^{4} \sec \left (d x + c\right ) + a^{2} e^{4} \csc \left (d x + c\right )^{4}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\left (e \csc \left (d x + c\right )\right )^{\frac{7}{2}}{\left (a \sec \left (d x + c\right ) + a\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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